JEE Main 2018 — Alcohols Phenols And Ethers Question with Solution
From: JEE Main 2018 (Offline)
Question
The major product formed in the following reaction is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
(1)
Here oxygen(O) has lone so it will attach on H+ of HI and H+ will attach with O atom to form oxonium ion.
(2)
As O is more electronegative atom, so it don't want to hold the positive charge so it will break bond to create 2o cation which is stable.
Now with this cation I ion is added.
(3) On the other oxygen atom similar method is applied.
Here oxygen(O) has lone so it will attach on H+ of HI and H+ will attach with O atom to form oxonium ion.
(2)
As O is more electronegative atom, so it don't want to hold the positive charge so it will break bond to create 2o cation which is stable.
Now with this cation I ion is added.
(3) On the other oxygen atom similar method is applied.
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This is a previous-year question from JEE Main 2018, covering the Alcohols Phenols And Ethers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.